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Force type conversion<\/p>\n
I have two classes which have the same method names but different type definitions. Is there a simple way to force the conversion in both directions without creating a helper function for each class? Here’s my code, with x being 1.0 and y being a string:
\nclass A {
\npublic:
\n int val() {
\n return 1;
\n }
\n};<\/p>\n
class B {
\npublic:
\n int val() {
\n return 1;
\n }
\n};<\/p>\n
B foo(A x) {
\n return x;
\n}<\/p>\n
void foo2(B y) {
\n B x(y);
\n}<\/p>\n
int main() {
\n B x(“foo”);<\/p>\n
std::cout<\/p>\n","protected":false},"excerpt":{"rendered":"
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